Combinations 0-9 (4 Digit)

[nyana]

So theoretically a Sentry safe has a digital lock system, with keypads of numbers 0-9....the combination maximum limit is four digits. How many possible combinations of numbers could come out of this? Can someone give me advice, a program to use to calculate all possible combinations? How many, essentially would there be?

0-1-2-3-4-5-6-7-8-9

FULL COMBINATION IS FOUR DIGITS LONG, so how many combinations could those numerics make, and what would they be? IS there some sort of program I can use, or tool to get every possible outcome of these numbers, in four digit length?

Thanks, and take care.

[cjames73]

hi nyana, welcome to the site.
discussions on safe opening are restricted to the advanced forums only.

[Urbex]

If I did the math correctly, 362880 possible combinations.

You will be sitting there for a long, long, long time.

[keysman]

IS there some sort of program I can use, or tool to get every possible outcome of these numbers, in four digit length?

Yes there is tool.. been around for centuries

Pencil + paper (Lines make it a little easier but not necessary)
Take sharp pencil write 0000 on the paper
next line write 0001
next line write 0002

continue on until you have written down all possible 4 digit combinations
sharpen pencil as necessary.

[Safety0ff]

If I did the math correctly, 362880 possible combinations.

I got a much smaller number than that because there's 10 possible digits and 4 slots or there's 10 possible digits and 1 to 4 slots. I know where you got that answer from: 9!=9*8*7*6*5*4*3*2*1=362880
Problems with your math:
-0 is a digit don't forget to count it.
-Assumes the same digit isn't used twice.
-Allows for 9 digit combination.

[poor paperclip picker]

If I did the math correctly, 362880 possible combinations.

I got a much smaller number than that because there's 10 possible digits and 4 slots or there's 10 possible digits and 1 to 4 slots. I know where you got that answer from: 9!=9*8*7*6*5*4*3*2*1=362880
Problems with your math:
-0 is a digit don't forget to count it.
-Assumes the same digit isn't used twice.
-Allows for 9 digit combination.

if all that is true, which i took in account, you should get a larger number than 362880, not a smaller number. I got 1048576.

[Safety0ff]

if all that is true, which i took in account, you should get a larger number than 362880, not a smaller number. I got 1048576.

I think you might have inverted your exponent/power with your base .

[poor paperclip picker]

if all that is true, which i took in account, you should get a larger number than 362880, not a smaller number. I got 1048576.

I think you might have inverted your exponent/power with your base .

yeah I couldn't remember which one went where... oops my bad

but it makes sense to me, number of slots with number of possible digits... I don't know its been awhile since my algebra days..

[poor paperclip picker]

i guess either way there is going to be a lot of combos... so nyana do not try breaking into the safe...

[Safety0ff]

Who says it'll let you try all the combos anyways.

[keysman]

=362880

if all that is true, which i took in account, you should get a larger number than 362880, not a smaller number. I got 1048576.[/quote]

If I did the math correctly, 362880 possible combinations.

You will be sitting there for a long, long, long time.

Hold on ! If there can only be 4 digits than the largest # will be 9999 starting at 0000 that leaves 10,0000 possible combinations not 362K or more

[Safety0ff]

Hold on ! If there can only be 4 digits than the largest # will be 9999 starting at 0000 that leaves 10,0000 possible combinations not 362K or more

Precisely. I was just correcting the other ppl but I didn't want to help nyana. It's quite simple to find out how many possible combo's there is whether using mathematical methods or rationalising it as you have.
I knew it was 10k. Proof:

I think you might have inverted your exponent/power with your base .

4^10=1 048 576
10^4= 10 000
If you look at it as 4 is the maximum number of digit then the answer is:
10^4+10^3+10^2+10=11 110.

[Urbex]

Well I tried, but it doesn't matter...

It's still going to be a ridiculous amount of combinations.

[mcm151201]

Not to mention that the safe will lock out for a while after a certain number of incorrect attempts are made, so sitting at it trying all possible combinations would take and exceedingly massive amount of time. Theoretically of course

[FFVison]

10 possible digits per wheel: 0...9

for each digit of the combination, you multiply the numbers together, so for a 2 digit combination, it's 10 * 10 or 100. For 3 digits, it's 10 * 10 * 10 which is 1000. This pattern could be simplified by the following equation (number of digits)^(number of wheels you need to turn to the correct digit). If you are only working with wheels with 10 digits going from 0 to 9, it should be easy to figure out. The working combination is a 4 digit number with a value somewhere between 0000 and 9999, so you have exactly 10,000 possible combinations. After typing for a bit, I realized that you are dealing with pushing buttons to get the number, not turning wheels, but it's the same principle for figuring out the maximum number of combinations.