GWiens2001 wrote:If the stack for bitting #3 has an extra master wafer, perhaps you could have the extra control key at that point. File/cut all other bittings exactly the same as your first control key. Then cut/file the third bitting to the next lower master pin split, which should be the next bitting at the control shear line. Remember, this will probably not be as deep a cut as your origional control key. To be more specific, and save you time, it will be a shallower cut by the height of the second pin from the top on that stack.
This is, of course, assuming that your first control key was cut to just below the control shear line on each pin stack. If this works (which it should), you may have found the second (for the first lock), proper control key that will work on both locks. If the locksmith who assembled the first lock accidentally lost his space and dropped in an extra pin in the third position, it would not change the operating or origonal control key, but would create an additional control (and possible additional operating) key.
Good luck,
Gordon
I understand this, I would try this, but there is no biting that would put the pins at another shear line. This is what I was trying to illustrate with the second and third pictures. If I have understood everything correctly, I think I have the only possible option.
Pin 3 as an example: to achieve the shear line for the control, the key has a very shallow cut already. If I insert a blank, to show the maximum range, it doesnt push the top pin high enough to reach another shear line.
Does this make sense/ is it correct logic?
