by Mikeh727 » 29 May 2014 2:02
Funkja,
It looks like four numbers in the combination.
Based on the drawings and an opening sequence that I found, you might be able to brute force less than 40 combinations and get this thing open. That's a big might....I am not familiar with this lock but it might be worth a try.
The opening sequence I found on line was two times left to the first number, then right to the second, left to the third, and right to the fourth. Each of the second two numbers was contained within the first two. The combination on the one that I found was left 2X to 7,right to 11, left to 8, right to 9. So, 7 and 11 are 5 numbers apart, and the other numbers are all within those two numbers.
The diagrams on that link seem to support this type of combination. I would try picking two number that are 5 numbers apart as your starting point, such as 12 and 4. Go R 2X to 12, L4, R1, L2. Then try the same first two, but then R2, L3. Then the same first two and R1, L3.
With only 12 pairs of numbers to start with and three combinations per pair, that's 36 possible combinations to try.
It's a shot in the dark but if it were mine, that's how I would start.
Good luck, let us know how it goes!
-Mike
